Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A body is projected at an angle of $60^\circ $ with the horizontal. If its kinetic energy at its maximum height is $10 \, J$ , then the height at which its potential energy and kinetic energy have equal values is (consider potential energy at the point of projection to be zero)

NTA AbhyasNTA Abhyas 2020Motion in a Plane

Solution:

KE at maximum height
$\frac{1}{2} \text{mu}^{2} \text{cos}^{2} 6 0^{^\circ } = 1 0 J$
$\frac{1}{2} \text{mu}^{2} = 4 0 J$
$Mg \text{H}_{\text{max}} = 3 0 J$ ...(i)
When $\text{PE} = \text{KE}$
$⇒ \, \, \, \text{mgh} = 2 0 =$ ...(ii)
from (i) and (ii)
$\frac{\text{h}}{\text{H}_{\text{max}}} = \frac{2}{3}$