1. Tardigrade
  2. Question
  3. Physics
  4. A body has equal amount of rotational kinetic energy and translational kinetic energy while rolling without slipping on a horizontal surface. Given body is an example of

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A body has equal amount of rotational kinetic energy and translational kinetic energy while rolling without slipping on a horizontal surface. Given body is an example of

NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion

Solution:

Translational Kinetic Energy $= \frac{1}{2} m v^{2}$
Rotational Kinetic Energy $= \frac{1}{2} I \omega ^{2}$
Translational Kinetic Energy = Rotational Kinetic Energy
$\frac{1}{2}mv^{2}=\frac{1}{2}I\omega ^{2}$
Put $v=r\omega $ , you will get $I = M R^{2}$ which is inertia of ring.