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Q. A body floats with one-third of its volume outside water and 3/4 of its volume outside another liquid. The density of the other liquid is

Mechanical Properties of Fluids

Solution:

Let V be volume of the body.
In water weight of body = weight of water displaced
$=\frac{2}{3}V\times1\times g$
In another liquid, weight of body
= $\frac{2}{3}Vg=\frac{1}{4}V\rho g$
or $\rho=\frac{8}{3}g cc^{-1}$