Q.
A bob is hanging over a pulley inside a car through, a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration '$a$' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration '$a$' vertically. The tension in the string is equal to -
BITSATBITSAT 2013
Solution:
Applying Newton’s law along string
$T - m \sqrt{ a ^{2}+ g ^{2}}= ma$
$T = ma + m \sqrt{ a ^{2}+ g ^{2}}$