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Q. A blue lamp mainly emits light of wavelength $4500\, \mathring{A}$The lamp is rated at $150 \,W$ and $8\%$ of the energy is emitted as visible light. The number of photons emitted by the lamp per second is

Dual Nature of Radiation and Matter

Solution:

Number of photons emitted per second
$\frac{8\% of P}{E}=\frac{8P\lambda}{100 hc}=\frac{8\times150\times4500\times10^{-10}}{100\times6.63\times10^{-34}\times3\times10^{8}}$
$=3\times10^{19}$ photons per second