Question

A block slides down an inclined plane with an acceleration $g/2$ as shown in fig. Then coefficient of kinetic friction is :-

• A. $\sqrt{3}$
• B. $\sqrt{3}-1$
• C. $\frac{\sqrt{3}}{2}$
• D. $\frac{1}{\sqrt{3}}$

Answer 1

Answer: (B)

$mgsin\theta -f=ma$
$mgsin\theta -\mu mgcos\theta =ma$
$q=60^\circ a=g/2$
$g\left(sin 60 ^\circ - m cos 60 ^\circ \right)=g/2$
$\frac{\sqrt{3}}{2}-\mu \left(\frac{1}{2}\right)=\frac{1}{2}$
$\sqrt{3}-1=\mu $