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Q. A block rests on a horizontal table which is executing SHM in the horizontal plane with an amplitude ' $a$ '. If the coefficient of friction is ' $\mu$ ', then the block just starts to slip when the frequency of oscillation is

Oscillations

Solution:

For the block is about to slip, $\mu g=\omega^2$ a
$\omega=\sqrt{\frac{\mu g}{a}} \Rightarrow v=\frac{1}{2 \pi} \sqrt{\frac{\mu g}{a}}$