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  4. A block performs simple harmonic motion with equilibrium point x=0 . Graph of acceleration of the block as a function of time is shown. Which of the following statement is correct about the block? <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-wtmc7ybzqrpc.png />

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Q. A block performs simple harmonic motion with equilibrium point $x=0$ . Graph of acceleration of the block as a function of time is shown. Which of the following statement is correct about the block?

Question

NTA AbhyasNTA Abhyas 2020Oscillations

Solution:

Solution
From the figure given in the question, the speed of block will be maximum at $t=0, \, 2 \, and \, 4$ . So, the block can execute the simple harmonic motion. At extreme points at time $t=1 \, s$ and $t=3 \, s$ , the direction of acceleration is changed. So, at $t=4 \, s$ the speed of the block is maximum.