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Q. A block of mass $m$ slides down the plane inclined at angle $30^{\circ}$ with an acceleration $\frac{g}{4}$. The value of coefficient of kinetic friction will be:

JEE MainJEE Main 2023Laws of Motion

Solution:

$Mg \sin 30^{\circ}-\mu mg \cos 30^{\circ}= ma$
$\frac{g}{2}-\frac{\sqrt{3}}{2} \cdot \mu g=\frac{g}{4}$
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