Q. A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is
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Solution:
Let acceleration of system (rope + block) is a along the direction of applied force. Then,
$ a=\frac{P}{M+m} $ Draw the FBD of block and rope as shown in figure.
where, T is the required parameter. For block T=Ma $ \Rightarrow $ $ T=\frac{MP}{M+m} $

