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Q. A block of mass $m$ and charge $q$ is released on a long, smooth inclined surface. The magnetic field $B$ is constant, uniform, horizontal and parallel to the surface as shown. If the time from start when the block loses contact with the surface is $\frac{m \cot \theta}{k \cdot q B}$, then find $k$.Physics Question Image

Moving Charges and Magnetism

Solution:

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$f_{B}=m g \cos \theta$
$q v B=m g \cos \theta$
$q[g(\sin \theta t)] B=m g \cos \theta$
$\Rightarrow t=\frac{m \cot \theta}{q B}$