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Q. A block of mass $2 \,kg$ rests on a rough inclined plane making an angle of $30^\circ$ with the horizontal. The coefficient of static friction between the block and the plane is $0.7$. The frictional force on the block is

IIT JEEIIT JEE 1980Laws of Motion

Solution:

Since, $ m g \cos \theta > mg \sin \theta$
$\therefore $ Force of friction is = $mg \sin \theta$