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Q. A block of mass 2 kg is moving with initial velocity 10 m/s enters on a rough horizontal surface. An extra force of 20 N is opposing the motion and trying to stop the block. The time after which the block will stop momentarily is ($g\, =\, 10\, m/s^2$)Physics Question Image

Solution:

$F_{net}\,20+0.5\times 20 \,=\,30\,N$
Reatardation a = $\frac {F_{net}}{m}=\frac{30}{2} = 15m/s^2$
$t = \frac{v}{a}=\frac{10}{15}=0.67s$