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  4. A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force of 2.5 N is applied on the block as shown in the figure, the frictional force between the block and the floor will be

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Q. A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force of 2.5 N is applied on the block as shown in the figure, the frictional force between the block and the floor will bePhysics Question Image

ManipalManipal 2013Laws of Motion

Solution:

Given:
$\mu=0.4 \quad F =2.5 N$
$m =2 kg$
$N = mg =20 N$
The max value of friction $=\mu N =0.4 \times 20=8 N$
Since, the force applied is $2.5 N$ there is no need for friction to attain its max.
value.
$\therefore $ Frictional force $=2.5 N$