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  4. A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms -1. The coefficient of friction between the surface and bock is 0.5. The distance covered by the block before coming to rest is: [use g =9.8 ms -2 ]

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Q. A block of mass $10\, kg$ starts sliding on a surface with an initial velocity of $9.8 \,ms ^{-1}$. The coefficient of friction between the surface and bock is $0.5$. The distance covered by the block before coming to rest is : [use $g =9.8\, ms ^{-2}$ ]

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Solution:

$a =-\mu g =-0.5 \times 9.8=-4.9\, m / s ^{2}$
$d =\frac{ v ^{2}}{2 a }=\frac{9.8 \times 9.8}{2(4.9)}$
$=9.8 \,m$