1. Tardigrade
  2. Question
  3. Physics
  4. A block of mass 10 kg slides down a rough slope which is inclined at 45° to the horizontal. The coefficient of sliding friction is 0.30. When the block has slide 5 m, the work done on the block by the force of friction is nearly

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A block of mass $10\,kg$ slides down a rough slope which is inclined at $45^{\circ}$ to the horizontal. The coefficient of sliding friction is $0.30$. When the block has slide $5\, m$, the work done on the block by the force of friction is nearly

Work, Energy and Power

Solution:

As, $F=\mu m g \cos \theta$
or$F=0.30 \times 10 \times 10 \cos 45^{\circ}$
or$F=\frac{30}{\sqrt{2}} N$
$W=F \times s=\frac{30}{\sqrt{2}} \times 5 $
$=\frac{150}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}=75 \sqrt{2}\, J$
This is negative work because $F$ and $s$ are oppositely directed.