1. Tardigrade
  2. Question
  3. Physics
  4. A block of mass 1 kg slides down a curved track that is one quadrant of a circle of radius 1 m. Speed of the block at the bottom is 2 m / s. Work done by the frictional force on the block when it reaches at the bottom is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A block of mass $1\, kg$ slides down a curved track that is one quadrant of a circle of radius $1\, m$. Speed of the block at the bottom is $2\, m / s$. Work done by the frictional force on the block when it reaches at the bottom isPhysics Question Image

ManipalManipal 2016

Solution:

Given, $m =1\, kg$,
$v =2\, m / s$
$R =1\, m$
$W =?$
From energy conservation,
$m g h+ W=\frac{1}{2} m v^{2}$
$=\frac{1}{2} m v^{2}-m g h$
$=\frac{1}{2} \times 1(2)^{2}-1 \times 10=-8\, J$