Q.
A block of mass $1\, kg$ is pulled along the curve path $A C B$ by a tangential force as shown in figure. The work done by the frictional force when the block moves from $A$ to $B$ is
Work, Energy and Power
Solution:
Work done by friction
$=\int \vec{F} \cdot \overrightarrow{d s}=\int\limits_0^x \mu m g \cos \theta \frac{d x}{\cos \theta}=\mu m g x=20\, J$