Thank you for reporting, we will resolve it shortly
Q.
A block of mass $1 \,kg$ is held at rest against a rough vertical surface by pushing by a force F horizontally. The coefficient of friction is $0.5.$ When
Laws of Motion
Solution:
Minimum value of force $F$ to keep block at rest
$\mu F = mg ( F = N ) $
$\Rightarrow 0.5 F =0.1 \times 10 $
$\Rightarrow F =20\, N$
That means if $F \geq 20\, N$ friction will be equal to $mg (10 \,N )$
