1. Tardigrade
  2. Question
  3. Physics
  4. A block of ice of mass 50 kg is sliding on a horizontal plane. It starts with speed 5 m / s and stops after moving through some distance. The mass of ice that has melted due to friction between the block and the surface is (assuming that no energy is lost and latent heat of fusion of ice is 80 cal / g , J =4.2 J / cal )

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Q. A block of ice of mass $50 kg$ is sliding on a horizontal plane. It starts with speed $5 m / s$ and stops after moving through some distance. The mass of ice that has melted due to friction between the block and the surface is (assuming that no energy is lost and latent heat of fusion of ice is $80 cal / g , J =4.2 J / cal )$

Thermal Properties of Matter

Solution:

Given, $m=50 kg , v =5 ms ^{-1}, L =80 cal / g$
$J =4.2 J / cal$
Heat lost, i.e, $Q_{1}=$ work done $=$ change in kinetic energy
$= K$
$K =$ kinetic energy
i.e., $\frac{1}{2} mv ^{2}=\frac{1}{2} \times 50 \times 5^{2}=625 J$
and heat gained, i.e.
$Q _{2}= m ' \times L =80 \times m ' \times 4.2$
heat lost = heat gained
$\therefore Q _{1}= Q _{2}$
$625= m ' \times 8 \times 42$
$m '=1.86 g$