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Q. A block is moved from rest through a distance of $4\, m$ along a straight line path. The mass of the block is $5\, kg$ and the force acting on it is $20\, N$. If the kinetic energy acquired by the block be $40\, J$, at what angle to the path is the force acting?

Work, Energy and Power

Solution:

Let required angle is $\theta$.
Work done $=$ change in $KE$
$\Rightarrow F s \cos \theta=40-0$
$\Rightarrow 20 \times 4 \cos \theta=400$
$\Rightarrow \theta=60^{\circ}$