Q.
A block is kept on a frictionless inclined surface with angle of inclination '$\alpha$'. The incline is given an acceleration a to keep the block stationary. Then a is equal to :
AIEEEAIEEE 2005Laws of Motion
Solution:
In the frame of wedge, the force diagram of block is shown in figure. From free body diagram of wedge.
For block to remain stationary,
$ma\, cos\, \alpha = mg\, sin\, \alpha$
$a=g\,tan \, \alpha$
