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Q. A block has dimensions $1\, cm\, 2\, cm$ and $3\, cm .$ Ratio of the maximum resistance to minimum resistance between any pair of opposite faces of this block is

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Solution:

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$R_{\max }=\rho \frac{l_{\max }}{A_{\min }}=\rho \frac{3}{2}$
$R_{\min }=\rho \frac{l_{\min }}{A_{\max }}=\rho \frac{1}{6}$
$\therefore \frac{R_{\max }}{R_{\min }}=\frac{3}{2} \times \frac{6}{1}=9: 1$