Q.
A block A weighing 100 kg rests on a block B and is tied with a horizontal string to the wall at C. Block B weighs 200kg. The coefficient of friction between A and B is 0.25 and between B and the surface is $ \frac{1}{3}. $ The horizontal force P necessary to move the block B should be $ (g=10m/{{s}^{2}}) $
Jharkhand CECEJharkhand CECE 2010
Solution:
Friction between block A and block B and between block B and surface will oppose the P.
$ \therefore $ $ P={{F}_{AB}}+{{F}_{BS}} $
$ ={{\mu }_{AB}}{{m}_{A}}g+{{\mu }_{BS}}({{m}_{A}}+{{m}_{B}})g $
$ =0.25\times 100\times 10+\frac{1}{3}(100+200)\times 100 $
$ =1250\,N $
