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  4. A bird of mass 1.23 kg is able to hover by imparting t downward velocity of 10 ms-1 uniformly to air o density ρ kg-m-3 over an effective area 0.1 m2. If the acceleration due to gravity is 10 ms-2 then the magnitude of ρ is in kg-m-3

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Q. A bird of mass 1.23 kg is able to hover by imparting t downward velocity of $10 ms^{-1}$ uniformly to air o density $\rho kg-m^{-3}$ over an effective area $0.1 m^2$. If the acceleration due to gravity is $10 ms^{-2}$ then the magnitude of $\rho\, is\, in\, kg-m^{-3}$

EAMCETEAMCET 2003Mechanical Properties of Fluids

Solution:

The density is given by
$\rho=\frac{Mass}{Volume}=\frac{M}{V}=\frac{M}{Av}$
$=\frac{100}{0.1\times10}=1.23 kg-m^{-3}$