Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A biconvex lens forms a real image of an object placed perpendicular to its principal axis. Suppose the radii of curvature of the lens tend to infinity. Then the image would

Ray Optics and Optical Instruments

Solution:

$\frac{1}{f}=(\mu-1)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)$
For biconvex lens $R_{2}=-R_{1}$
$\therefore \frac{1}{f}=(\mu-1)\left(\frac{2}{R}\right)$