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  4. A beam of ions with velocity 2 × 105 m / s enters normally into a uniform magnetic field of 4 × 10-2 tesla. If the specific charge of the ion is 5 × 107 C / kg then the radius of the circular path described will be

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Q. A beam of ions with velocity $2 \times 10^{5} m / s$ enters normally into a uniform magnetic field of $4 \times 10^{-2}$ tesla. If the specific charge of the ion is $5 \times 10^{7} C / kg$ then the radius of the circular path described will be

Moving Charges and Magnetism

Solution:

$r =\frac{ mv }{ Bq }=\frac{ v }{\frac{ q }{ m } \times B }=\frac{2 \times 10^{5}}{5 \times 10^{7} \times 4 \times 10^{-2}}=0.1 m$
$r=0.1 m$