Question

A beaker containing a liquid of density $\rho$ moves up with an acceleration ' $a$ '. The pressure due to the liquid at a depth $h$ below free surface of the liquid is

• A. $h \rho g$
• B. $h \rho(g-a)$
• C. $h \rho(g+ a)$
• D. $2 h \rho g\left(\frac{g+ a}{g-a}\right)$

Answer 1

Answer: (C)

Due to upward acceleration pseudo force will act downwards so value of acceleration due to gravity will increase by '$a$ '
$\therefore g'=(g +a)$
$P=\rho g 'h$
$\Rightarrow P=\rho(g +a) h$
(Substitute $g'$ )