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Q. A bead of mass $m$ can slide on a frictionless wire as shown in figure. Because of the given shape of the wire, near $P$, the bottom point, it can be approximated as parabola. $\operatorname{Near} P$, the potential energy of the bead is given $U=c x^{2}$ where $c$ is a constant and $x$ is measured from $P$. The bead, if displaced slightly from point $P$ will oscillate about $P$. The period of oscillation isPhysics Question Image

Oscillations

Solution:

$U=C x^{2}$
$F=-\frac{d U}{d x} \Rightarrow m a=-2 c x $
$\Rightarrow a=-\frac{2 c}{m} x$
$\Rightarrow \omega=\sqrt{\frac{2 c}{m}} $
$\Rightarrow T=\frac{2 \pi}{\omega} = 2 \pi \sqrt{\frac{m}{2 c}}$