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Q.
A battery of e.m.f. $10\, V$ is connected to resistance as shown in figure. The potential difference $V_{A}-V_{B}$ between the points $A$ and $B$ is
Current Electricity
Solution:
$R_{e q}=5\, \Omega$, Current $i=\frac{10}{5}=2\, A$
and current in each branch $=1 \,A$
Potential difference between $C$ and $A$,
$V_{C}-V_{A}=1 \times 1=1 \,V$ .......(i)
Potential difference between $C$ and $B$,
$V_{C}-V_{B}=1 \times 3=3 \,V$ ...... (ii)
On solving (i) and (ii), $V_{A}-V_{B}=2\, V$
