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  4. A battery of 2 V emf and internal resistance 1 Ω sends a current of 1 A through an external load. If two such batteries are connected in series, the current through same load is

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Q. A battery of $2 \,V$ emf and internal resistance $1 \,\Omega$ sends a current of $1 \,A$ through an external load. If two such batteries are connected in series, the current through same load is

Solution:

Let $R=$ External resistance
$I=\frac{2}{1+R}($ first case $)\therefore R=1\, \Omega$
When two batteries are connected emf becomes
$4\, V$ and internal resistance $2 \,\Omega .$
$I=\frac{4}{1+2}=\frac{4}{3}=1.33 \,A$