1. Tardigrade
  2. Question
  3. Physics
  4. A battery of 10 V and negligible internal resistance is connected across the diagonally opposite corners of a cubical network consisting of 12 resistors each of resistance 1 Ω. The current through the battery is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A battery of $10 V$ and negligible internal resistance is connected across the diagonally opposite corners of a cubical network consisting of 12 resistors each of resistance $1 \Omega$. The current through the battery isPhysics Question Image

Current Electricity

Solution:

Using symmetry and junction rule, we can arrange the currents as shown. Applying loop rule along ABCD and battery to A, we get
$-i R-\frac{i}{2} R-i R+10=0$
As $R=1 \Omega$
$\therefore 10=\frac{5 i R}{2}=\frac{5 i}{2}$
or $i=\frac{20}{5}=4 A$
Current through the battery is $3i=12 A$.
image