Thank you for reporting, we will resolve it shortly
Q.
A batsman scores $38,76,34,48,44,54, 46,55,63,42$ runs in $10$ innings. Find the value of mean deviation about the median.
Statistics
Solution:
On arranging the given data in ascending order we get,
$34,38,42,44,46,48,54,55,63,76$
Here, $N =10$. (even.)
$\Rightarrow$ Median $=$ Average of $\left(\frac{ N }{2}\right)^{\text {th }}$ and
$\left(\frac{ N }{2}+1\right)^{\text {th }} $ terms
$=\frac{46+48}{2}$
$=47$
$\Rightarrow$ Mean deviation about median
$\Rightarrow \frac{\sum \mid x-\text { Median } \mid}{ N }$
$\Leftrightarrow \frac{\sum|x-47|}{10}$
$\Leftrightarrow \frac{13+9+5+3+1+1+7+8+16+29}{10}$
$\Rightarrow \frac{92}{10} \Leftrightarrow 9.2$