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Q. A batsman hits a ball from the ground level with speed of $28 \,ms ^{-1}$ in a direction $30^{\circ}$ above the horizontal. How far from the batsman does the ball land for the first time?

Motion in a Plane

Solution:

$R=\frac{u^{2} \cdot \sin 2 \theta}{g}=\frac{(28)^{2} \cdot \sin 2\left(30^{\circ}\right)}{9.8}=69\, m$