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Q. A bar magnet used in a vibration magnetometer is heated so as to reduce its magnetic moment by $19 \%$. The periodic time of the magnetometer will

Magnetism and Matter

Solution:

$T=2 \pi \sqrt{\frac{I}{M B}}$
and $T'=2 \pi \sqrt{\frac{I \times 100}{81\, M B}}$
$\Rightarrow T'=\frac{10}{9} T$
Percentage increase $= \frac{\frac{10}{9}-1}{1} \times 100$
$=\frac{1}{9} \times 100 \approx 11 \%$