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Q. A bar-magnet of moment of inertia $49 \times 10^{-2}\, kg - m ^{2}$ vibrates in a magnetic field of induction $0.5 \times 10^{-4} T$. The time period of vibration is $8.8\, s$. The magnetic moment of the bar magnet is

EAMCETEAMCET 2007

Solution:

Time period of magnet is
$T=2 \pi \sqrt{\frac{I}{M H}}$
or $M= \frac{4 \pi^{2} I}{T^{2} H}$
or $M=\frac{4 \times(3.14)^{2} \times 49 \times 10^{-2}}{(8.8)^{2} \times 0.5 \times 10^{-4}}$
or $M=5000\, A - m ^{2}$