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  4. A bar magnet is placed in the position of stable equilibrium in a uniform magnetic field of induction B. If it is rotated through an angle 180° , then the work is (M = magnetic dipole moment of bar magnet)

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Q. A bar magnet is placed in the position of stable equilibrium in a uniform magnetic field of induction B. If it is rotated through an angle $180^\circ $, then the work is (M = magnetic dipole moment of bar magnet)

J & K CETJ & K CET 2011Magnetism and Matter

Solution:

W = $MB(1-cos \,\theta)$ and = $MB(1 -cos 180^\circ) = 2MB$