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Q.
A balloon is rising vertically up with a velocity of $29\, ms^{-1}$. A stone is dropped from it and it reached ground in $10$ seconds. The height of the balloon when the stone was dropped from it is
For a stone which is thrown downwards from a balloon rising upwards, the equation of motion is
$h =- ut +\frac{1}{2} gt ^2 $
$=-29 \times 10+\frac{1}{2} \times 9.8 \times(10)^2 $
$=-290+490 $
$=200 m .$