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Q. A balloon is filled upto $3 / 4^{\text {th }}$ of its maximum stretching capacity at $30^{\circ} C$. The temperature upto which the balloon can be safely heated at constant pressure is ______.

States of Matter

Solution:

Let the maximum stretching capacity of the balloon is $V\, L$. From

$V _{1}=3 V / 4 L \,\,\,T _{1}=273+30=303 K$

$V _{2}= VL \,\,\,T _{2}=?$

From Charles law: $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

$\frac{\left(\frac{3 V}{4}\right)}{303}=\frac{V}{T_{2}}$

$T_{2}=404 \,K =131^{\circ} C$

Up to this temperature, balloon will not burst. It will burst when temperatures just exceeds this value. Hence, $131^{\circ} C$ is the limiting temperature, up to which balloon can be heated safely.