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  4. A ball of mass 2 kg and another of mass 6 kg are dropped together from a 80 feet tall building. After a fall of 50 feet each towards the earth, their respective kinetic energies will be in the ratio of

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Q. A ball of mass $2 kg$ and another of mass $6 kg$ are dropped together from a $80$ feet tall building. After a fall of $50$ feet each towards the earth, their respective kinetic energies will be in the ratio of

Work, Energy and Power

Solution:

Decrease in P.E = Gain in K.E energies.
$m g\left(h_{1}-h_{2}\right)=k_{f}-k_{i} \quad\left(k_{i}=0\right)$
$\frac{m_{1} g\left(h_{1}-h_{2}\right)=k_{f_{1}}}{m_{2} g\left(h_{1}-h_{2}\right)=k_{f_{2}}} \Rightarrow \frac{m_{1}}{m_{2}}=\frac{k_{f_{1}}}{k_{f_{2}}} \Rightarrow \frac{1}{3}=\frac{k_{f_{1}}}{k_{f_{2}}}$