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Q. A ball is thrown vertically upward (taken as+z-axis) from the ground.Mark the correct momentum-height $\left(\right.p-h\left.\right)$ diagram :

NTA AbhyasNTA Abhyas 2020

Solution:

$\left|\right.p\left|\right.=mv=m\sqrt{u^{2} - 2 gh}\Rightarrow p^{2}=m^{2}u^{2}-2mgh$ $v^{2}=u^{2}-2gh$
$v=\sqrt{u^{2} - 2 gh}$