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  4. A ball is thrown horizontally from the top of a tower of height 8 m. It touches the ground at a distance of 90 m from the foot of the tower. The initial velocity of the body is:

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Q. A ball is thrown horizontally from the top of a tower of height $8\, m$. It touches the ground at a distance of $90\, m$ from the foot of the tower. The initial velocity of the body is:

Motion in a Plane

Solution:

According to the relation
$R = u \sqrt{\frac{2 h }{ g }}$
$\Rightarrow u = R \sqrt{\frac{ g }{2 h }}=90$
$\sqrt{\frac{10}{2 \times 8}}$
$u =90 \sqrt{\frac{10}{16}}$
$\Rightarrow u =\frac{90}{4} \sqrt{10}$
$\Rightarrow u =\frac{90}{4} \times 3.1$
$u =69.75$