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  4. A ball is projected with kinetic energy E, at an angle of 60° to the horizontal. The kinetic energy of this ball at the highest point of its flight will become :

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Q. A ball is projected with kinetic energy E, at an angle of $60^{\circ}$ to the horizontal. The kinetic energy of this ball at the highest point of its flight will become :

JEE MainJEE Main 2022Motion in a Straight Line

Solution:

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$E =\frac{1}{2} mu ^2$
At Highest point, Velocity $V = u \cos 60^{\circ}=\frac{ u }{2}$
$\therefore K . E$ at topmost point $=\frac{1}{2} m \left(\frac{ u }{2}\right)^2=\frac{ E }{4}$