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Q. A ball is projected with a velocity, $10\, ms ^{-1}$, at an angle of $60^{\circ}$ with the vertical direction. Its speed at the highest point of its trajectory will be :

NEETNEET 2022Motion in a Plane

Solution:

At highest point only horizontal component of velocity remains
$\Rightarrow u_{x}=u \cos \theta$
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$ u _{ x }= u \cos \theta =10 \cos 30^{\circ} $
$=5 \sqrt{3} \,ms ^{-1}$