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  4. A ball is projected from the ground with a speed 15 ms -1 at an angle θ with horizontal so that its range and maximum height are equal, then'tan θ ' will be equal to

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Q. A ball is projected from the ground with a speed $15\, ms ^{-1}$ at an angle $\theta$ with horizontal so that its range and maximum height are equal, then'tan $\theta$ ' will be equal to

JEE MainJEE Main 2022Motion in a Plane

Solution:

$R = H$
$ \frac{2 v _{ x } \times v _{ y }}{ g }=\frac{ v _{ y }^2}{2 g }$
$ v _{ x }=\frac{ v _{ y }}{4} ; u \cos \theta=\frac{ u \sin \theta}{4} $
$ \tan \theta=4$