Question

A ball is projected at an angle $60^\circ $ with the horizontal with speed $30 \, m/s$ . What will be the speed of the ball when it makes an angle $45^\circ $ with the horizontal?

• A. $30m/s$
• B. $15\sqrt{2}m/s$
• C. $\frac{15}{\sqrt{2}}m/s$
• D. $30\sqrt{2}m/s$

Answer 1

Answer: (B)

Horizontal velocity remains same $30^\circ cos60^\circ =vcos45^\circ $
$\Rightarrow v=15\sqrt{2}m/s$