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Q. $ A+B \rightleftharpoons C+D. $ If initially the concentration of $A$ and $B$ are both equal but at equilibrium, concentration of $D$ will be twice of that of $A$, then what will be the equilibrium constant of reaction?

JIPMERJIPMER 2006

Solution:

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$K_{c}=\frac{[C][D]}{[A][B]}=\frac{2 x \times 2 x}{x \times x}=4$