1. Tardigrade
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  4. A B are two independent events such that P( barA)=0.7, P( barB)=a P(A ∪ B)=0.8, then, a=

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Q. A \& $B$ are two independent events such that $P(\bar{A})=0.7, P(\bar{B})=a \& P(A \cup B)=0.8$, then, $a=$

Probability - Part 2

Solution:

$0.8=0.3+(1-a)-0.3(1-a) \Rightarrow a=2 / 7$