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  4. A 500 W heater is used to heat 250 mL of water from 20° C to 100° C. What is minimum time in which this can be done?

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Q. A $500 \,W$ heater is used to heat $250 \,mL$ of water from $20^{\circ} C$ to $100^{\circ} C$. What is minimum time in which this can be done?

Solution:

$H=P t=500 t=m s \Delta T$
$500 t=0.25 \times 4.184 \times 80 \times 1000$
$t=\frac{0.25 \times 1000 \times 80 \times 4.184}{500} $
$=167.4\, s$