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Physics
A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/h . The centripetal force is
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Q. A $ 500 \,kg $ car takes a round turn of radius $ 50\, m $ with a velocity of $ 36\, km/h $ . The centripetal force is
AIPMT
AIPMT 1999
Motion in a Plane
A
$ 250\,N $
12%
B
$ 750\,N $
15%
C
$ 1000\,N $
59%
D
$ 1200\,N $
14%
Solution:
Given , m = 500 kg,
$ \nu = 36\,kmh^{-1} = 36 \times \frac{5}{18} = 10 \,ms^{-1} $ , r = 50 m
$ F =\frac{m\nu^2}{r} $
Hence, $ F=\frac{500 \times (10)^2}{50} $ = 1000 N